.props() => Object

Returns the props hash for the root node of the wrapper. .props() can only be called on a wrapper of a single node.

NOTE: When called on a shallow wrapper, .props() will return values for props on the root node that the component renders, not the component itself.

To return the props for the entire React component, use wrapper.instance().props. This is valid for stateful or stateless components in React 15.*. But, wrapper.instance() will return null for stateless React component in React 16.*, so wrapper.instance().props will cause an error in this case. See .instance() => ReactComponent

Example


import PropTypes from 'prop-types';

function MyComponent(props) {
  const { includedProp } = props;
  return (
    <div className="foo bar" includedProp={includedProp}>Hello</div>
  );
}
MyComponent.propTypes = {
  includedProp: PropTypes.string.isRequired,
};

const wrapper = shallow(<MyComponent includedProp="Success!" excludedProp="I'm not included" />);
expect(wrapper.props().includedProp).to.equal('Success!');

// Warning: .props() only returns props that are passed to the root node,
// which does not include excludedProp in this example.
// See the note above about wrapper.instance().props.

console.log(wrapper.props());
// {children: "Hello", className: "foo bar", includedProp="Success!"}

console.log(wrapper.instance().props); // React 15.x - working as expected
// {children: "Hello", className: "foo bar", includedProp:"Success!", excludedProp: "I'm not included"}

console.log(wrapper.instance().props);
// React 16.* - Uncaught TypeError: Cannot read property 'props' of null